time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)
Answer from: Quest
b. would be the answer : )
step-by-step explanation:
step 1: add -16x to both sides.
16x−4y+−16x=64+−16x
−4y=−16x+64
step 2: divide both sides by -4.
−4y /-4 = -16x + 64/-4
answer: y=4x−16
hope i'm right
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