What is the equation of the quadratic graph with a focus of (-1,4) and a directrix of y=2? hint: y=a(x-h)^2+k, a=1/4p

y = 1/4(x + 1)^2 + 3.

Step-by-step explanation:

The general form is (x - h)^2 = 4p(y - k)   where the focus is (h, k+p) and the directrix is y = k-p

So we have  h = -1

k + p = 4

k - p = 2 Adding:

2k = 6 so k = 3 and p = 1.

Therefore:

(x  + 1)^2 = 4(y - 3)

4y = (x + 1)^2 + 12

y = 1/4(x + 1)^2 + 3.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

answer: do we write it

step-by-step explanation: