Asingly charged positive ion has a mass of 3.20 ✕ 10-26 kg. after being accelerated from rest through a potential difference of 858 v, the ion enters a magnetic field of 0.920 t along a direction perpendicular to the direction of the field. calculate the radius of the path of the ion in the field.

Radius of the path will be

Step-by-step explanation:

We have given mass of the singly charged positive ion

Potential difference V = 858 volt

Magnetic force on the charge particle is given by , here q is charge v is velocity and B is magnetic field

And centripetal force is given by

These forces will be equal

So

We know that

Now radius

she will travel a distance in the range of 3 - 11 miles

13.46

step-by-step explanation:

16.80 x .20 = 13.46