The sum of two numbers is 43. the smaller number is 19 less than the larger number. what are the numbers?

So the answer is 12 and 31.

Step-by-step explanation:

Let the smaller number be x and the larger number be y.

We can calculate this by using simultaneous equation, aka listing 2 equations out.

From given,

X + y = 43

Let this be equation no. 1

X + 19 = y

Let this number be equation 2.

We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.

We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.

X + x + 19 = 43

Solve this by algebra.

2x = 43 - 19

X = 12

Now we know the exact value of x

Now substitute x = 12 into equation no. 2

12 + 19 = y

Y = 31

19.side- angle- side

20. angle- side- angle

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18