One number is 9 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 1123, find the numbers

ANSWER:

One number is 9 times a first number. The numbers are 93, 837 and 193.

SOLUTION:

Given, one number is 9 times a first number.  

A third number is 100 more than the first number.

The sum of the three numbers is 1123,  

We need to find the numbers.

let the first second and third numbers be a, b, c respectively

According to given information, b = 9a (1)

c = 100 + a (2)

a + b + c = 1123 (3)

now substitute (1) and (2) in (3)

a + 9a + 100 + a = 1123

11a + 100 = 1123

11a = 1123 – 100

11a = 1023

a = 93

now substitute a value in (1) and (2)

b = 9 x 93 = 837

c = 100 + 93 = 193

hence, the numbers are 93, 837, 193.

4th option is correct xy=-10

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3.how is solving radical equations different than solving linear equations?

step-by-step explanation: