Solve each of the following equations that include brackets: 3(2d-9)+5d=17, and 8c-4(c+3)=8

ANSWER:  

After solving the equations, values of d and c are 4, 5.

SOLUTION:

Given, two equations are 3(2d-9) + 5d = 17, and 8c - 4(c+3) = 8.  

Now, let us solve the first equation.

3(2d-9) + 5d=17  

On multiplying the terms within the bracket, we get

3 × 2d – 3 × 9 + 5d = 17

6d – 27 + 5d = 17

11d = 17 + 27

11d = 44

d = 4

Now, let us solve the second equation.

8c - 4(c+3) = 8

On multiplying the terms within the bracket, we get

8c – 4 × c – 4 × 3 = 8

8c – 4c – 12 = 8

4c = 8 + 12

4c = 20

c = 5

Hence, after solving the equations , values of d and c are 4, 5.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70