With theses math question! will mark brainliest 70 !

1. Let hardcover books = X

Paperback books would be 4x -3 ( 3 less than 4 times)

Now you have:

X + 4x-3 = 447

Simplify:

5x - 3 = 447

Add 3 to each side:

5x = 450

Divide both sides by 5:

x = 450/5

x = 90

He has 90 hardcover books.

2. 300 miles / 25 miles per gallon = 12 gallons of gas.

12 gallons x $$ per gallon = $48 dollars

3. Subtract base pay from total:

1916 - 800 = 1,116 worth of commissions.

Divide commissions by percentage:

1116 / 0.09 = $12,400 total sales.

4.

Find the median of the heights: 65-50 = 15. 15/2 = 7.5

Median = 50+7.5 = 57.5

The equation would be |h-57.5| < 7.5

32 ≤ cost ≤ 48 dollars.

Step-by-step explanation:

1. Let x be number of hardback books. Then:

x + 4x - 3 = 447

5x = 450

x = 90 hardbacks.

2. If she is 200 miles from her destination her car will use 200/25 = 8 gallons of gas, and cost her 8*4 = $32.

If the distance is 300 miles then the cost  will be  (300/25) * 4 =  $48.

3. He earned 1916 - 800 = $1116 commission on his sales.

4. ( I can't see any options).

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step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2