One pack of biscuits cost $x and one cup of ice cream costs $y. one packet and 2 cups of ice cream costs $8, while three packet of biscuits and one cup of ice cream cost $9. by solving determine the cost of both items

One pack of biscuits cost $x and one cup of ice cream costs $y. The cost of both the items are x = 2 and y = 3

Solution:

By solving determine the cost of both items

Step 1:

Say Biscuits=x and ice cream=y

Therefore: 1 pack biscuit and 2 cups ice cream = x+2y=8

3 pack biscuit and 1 cup ice cream = 3x+y=9

Step 2:

x+2y=8 (i)

3x+y=9 (ii)

Step 3:

To solve:

From equation i, x=8-2y

Substituting into (ii),

3(8-2y)+y=9

24-6y+y=9

24-5y=9

-5y=-15

y=3

Step 4:

To find x:

Place y=3 into (i)

x+2y=8

x+2(3) =8

Step 5:

x+6=8

x=8-6

x=2

Hence the cost of both the items biscuit and icecream is 2 and 3

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6