Amy, jean, keith, tom, susan, and dave have all been invited to a birthday party. they arrive randomly and each person arrives at a different time. in how many ways can they arrive? in how many ways can jean arrive first and keith last? find the probability that jean will arrive first and keith will arrive last.

a) 720, b) 24, c) 0.0333....

Step-by-step explanation:

Since we have given that

Number of people = 6

In how many ways can they arrive?

So, total possible ways would be

In how many ways can Jean arrive first and Keith last?

Since Jean take first place and keith takes the last place.

Remaining people = 4

so, number of ways would be

Find the probability that Jean will arrive first and Keith will arrive last.

So, probability would be

Hence, a) 720, b) 24, c) 0.0333....

you divide them and then you get the answer i took this class this year

step-by-step explanation:

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)