One year perry had the lowest era (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an era of 3.02. also, alice had the lowest era of any female pitcher at the school with an era of 3.16. for the males, the mean era was 4.206 and the standard deviation was 0.846. for the females, the mean era was 4.519 and the standard deviation was 0.789. find their respective z-scores. which player had the better year relative to their peers, perry or alice

z score Perry

z score Alice

Alice had better year in comparison with Perry.

Step-by-step explanation:

Consider the provided information.

One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.

To find z score use the formula.

Here μ=4.206 and σ=0.846

Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.

Find the z score

where μ=4.519 and σ=0.789

The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.

It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: your answer is a