The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. the distribution of the number of daily requests is bell-shaped and has a mean of 35 and a standard deviation of 6. using the 68-95-99.7% rule, what is the approximate percentage of light bulb replacement requests numbering between 35 and 41?

34%

Step-by-step explanation:

Given : The distribution of the number of daily requests is bell-shaped and has a and .

We can see that 41 = 35+6 , it 41 is one standard deviation from mean in the right side . (1)

According to the 68-95-99.7% rule, 68% of the population falls within 1 standard deviation from the mean.

34% (half of 68%) of the population on right side and 34% population on the left side of the density curve.              (2)

From (1) and (2), the approximate percentage of light bulb replacement requests numbering between 35 and 41= 34%

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

(-5,-28)

i graphed to on desmos.