Sophia works in a clothing store and earns $40 per day. she earns an extra $5 for each outfit she sells. if sophia wants to earn at least $70 per day, which inequality shows the minimum number of outfits, n, that she should sell? 40 + 5n ≤ 70, so n ≤ 6 40 + 5n ≥ 70, so n ≥ 25 40 + 5n ≤ 70, so n ≤ 25 40 + 5n ≥ 70, so n ≥ 6

angle efh= angle egh

2 1/2 feet

step-by-step explanation:

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )