Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. the 46-n pushing force modifying above p with right-arrow is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. find the magnitude of the force modifying above f with right-arrow that the 24-kg box applies to the 62-kg box.

33.16N

Step-by-step explanation:

The 46 N force is causing both boxes to accelerate. To determine the acceleration, we are going to use Newton's laws of motion

F=m*a --> a=F/m

You know that the Force is 46 and the mass is the sum of both boxes (cause you are moving the two of them)

a =46 ÷ (24 + 62) = 46 ÷ 86  

This is approximately 0.535 m/s. This is the acceleration of both boxes. To determine the force that the 24-kg box applies to the 62-kg box, you use the newton's law of motion. But now you know the acceleration and the mass

F=m*a=62*0.535m/s=33.16 N

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]