Two airplanes are flying in the same direction in adjacent parallel corridors. at time t = 0, the first airplane is 10 km ahead of the second one. suppose the speed of the first plane (km/hr) is normally distributed with mean 550 and standard deviation 9 and the second plane's speed is also normally distributed with mean and standard deviation 535 and 9, respectively. a) what is the probability that after 2 hr of flying, the second plane has not caught up to the first plane? (round your answer to four decimal places.)b) determine the probability that the planes are separated by at most 10 km after 2 hr. (round your answer to four decimal places.)

the first one, all those points on the line just make a strait line.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

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d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation: