Let the sample space be upper s equals startset 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 endsets={1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. suppose the outcomes are equally likely. compute the probability of the event eequals="an oddodd number less than 1010." upper p (upper e )p(e)equals=. 50.50 (type an integer or a decimal. do not round.)

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

h/o/e/s mad

step-by-step explanation:

si si si

step-by-step explanation:

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