Mathematics, 08.10.2019 23:20 laurenbreellamerritt
Unlike a decreasing geometric series, the sum of the harmonic series 1, 1/2, 1/3, 1/4, 1/5, . . di- log(n! ) = θ(n log n). verges; that is, it turns out that, for large n, the sum of the first n terms of this series can be well approximated as 1 ≈ ln n + γ, i=1 i where ln is natural logarithm (log base e = 2.718 . .) and γ is a particular constant 0.57721 . .. showthat 1 = θ(logn). i=1 i (hint: to show an upper bound, decrease each denominator to the next power of two. for a lower bound, increase each denominator to the next power of 2.)
Answers: 3
Mathematics, 21.06.2019 20:40
Which function has an inverse function? a.f(x)= |x+3|/5 b. f(x)= x^5-3 c. f(x)= x^4/7+27 d. f(x)= 1/x²
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Jim had 15 minutes to do 5 laps around his school what would his time be
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1. according to the internal revenue service, the mean tax refund for the year 2007 was $2,708. assume the standard deviation is $650 and that the amounts refunded follow a normal probability distribution. a. what percent of the refunds are more than $3,000? b. what percent of the refunds are more than $3,000 but less than $4,000? c. what percent of the refunds are less than $2,000?
Answers: 2
Unlike a decreasing geometric series, the sum of the harmonic series 1, 1/2, 1/3, 1/4, 1/5, . . di-...
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