Abag of 29 tulip bulbs contains 10 red tulip bulbs, 12 yellow tulip bulbs, and 7 purple tulip bulbs. (a) what is the probability that two randomly selected tulip bulbs are both red? (b) what is the probability that the first bulb selected is red and the second yellow? (c) what is the probability that the first bulb selected is yellow and the second red? (d) what is the probability that one bulb is red and the other yellow?

Answer

given,

A bag consist of 29 tulip bulbs

a) P(both bulb are red ) =

     =

     =

     = 0.111

P(both bulb are red ) = 0.111

b) P(first bulb is red and second yellow ) =

     =

     =

     = 0.148  

P(first bulb is red and second yellow ) = 0.148

c) P(first bulb is yellow and second red ) =

     =

     =

     =0.148

P(first bulb is yellow and second red ) = 0.148

d) P(one bulb is red and the other yellow) =

     = P(first bulb is yellow and second red ) + P(first bulb is red and second yellow )

     = 0.148 + 0.148

     = 0.296

P(one bulb is red and the other yellow) = 0.296

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus