Acafeteria has 5 turkey sandwiches, 6 cheese
sandwiches and 4 tuna sandwiches. there are two
students in line and each will take a sandwich. what is
the probability that the first student takes a cheese
sandwich and the next student takes a turkey
sandwich?

5 + 6 + 4 = 15 total sandwiches.

6 are cheese.

Probability 1st person picks cheese would be 6/15 = 2/5 ( 6 cheese sandwiches over total sandwiches).

After the 1st person takes a sandwich there are 14 left.

5 are turkey.

Probability the 2nd person picks turkey is 5/14 ( 5 turkey sandwiches over total sandwiches left).

The probability of both happening =

2/5 x 5/14 = (2 * 5) / (5 * 14) = 10/70 = 1/7

answer: idk

step-by-step explanation: