British and american spelling are `rigour' and `rigor', respectively. a man staying at a parisian hotel writes this word, and a letter taken at random from his spelling is found to be a vowel. if 40% of the english-speaking men at the hotel are british and 60% are americans, what is the probability that the writer is british?

45.45%

Step-by-step explanation:

Given:

British spelling as "rigour"

here Probability of selecting vowel , P(V/B) =  

or

Probability of selecting vowel , P(V/B) =   = 0.5

and,

American spelling as "rigor"

here Probability of selecting vowel , P(V/A) =  

or

Probability of selecting vowel , P(V/A) = = 0.4

Probability of English-speaking men at hotel are British P(B) = 40% = 0.4

Probability of English-speaking men at hotel are American P(A) = 60% = 0.6

Now using Baye's theorem

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) = 0.4545 = 45.45%

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!