Solve the system by elimination (show all work)

-2x +2y+3z=0,

-2x-y+z=-3,

2x+3y+3z=5

Step-by-step explanation:

{−2x + 2y + 3z = 0

{−2x - y + z = −3 ←

{2x + 3y + 3z = 5 ←

2y + 4z = 2 ↷

{−2x + 2y + 3z = 0 ←

{−2x - y + z = −3

{2x + 3y + 3z = 5 ←

5y + 6z = 5 ↷

{5y + 6z = 5

{2y + 4z = 2

−⅖[5y + 6z = 5]

{−2y - 2⅖z = −2 >> New Temporary Equation

{2y + 4z = 2

____________

1⅗z = 0

___ _

1⅗ 1⅗

[Plug this back into both equations above to get the y-term of 1, then plugging both z-term and y-term into all three equations at the very top, will give you the x-term of 1]; ;

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step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).