Apotential energy function for system 1 is given by u1(x)=cx2+bx3. the potential energy function for system 2 is given by u2(x)=a+cx2+bx3, where a is a positive quantity. how does the force on system 1 relate to the force on system 2 at a given position?

Step-by-step explanation:

  Given that

For system 1

For system 2

A is positive quantity

We know that

Force F

For system 1

For system 2

So from above equations we can say that force on both system is equal at given value of x.

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

it has the same slope and a different y-intercept

hope this : )