Arunner finishes a 200-meter dash in 35 seconds. let r represent any speed (in meters per second) faster than the runner's speed. write an inequality that represents r

Part a) (the graph in the attached figure)

Part b) see the explanation                                        

Step-by-step explanation:

The complete question is

A runner finishes a 200-meter dash in  35 seconds. Let r represent any speed (in meters  per second) faster than the runner’s speed.

a. Write an inequality that represents r. Then graph  the inequality.

b. Every point on the graph represents a speed faster  than the runner’s speed. Do you think every point  could represent the speed of a runner?

Part a)

we know that                                      

The speed of the runner is equal to divide the distance by the time

so              

Simplify                      

Let

r -----> represent any speed (in meters per second) faster than the runner's speed

The inequality that represent r is

using a graphing tool

The graph in the attached figure

The solution is all real numbers greater than 40/7 m/sec

Part b)

we know that

From a mathematical point of view, every point of the graph belong to the solution set , but from a practical point of view the runner's speed is physically limited, so the solution set is a boundary interval

3030 ur welcome

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.