Which expression is even for all integers a and b

E)ab + ab

Step-by-step explanation:

The following options are missing:

A)2a + b  

B)ab + 2a  

C)5a + 6b  

D)ab + 2b  

E)ab + ab

An expression is even when f(x) = f(-x). In this case, the arguments are a and b. Let's suppose a = 1, b = 1 and analyze every option:

A) 2a + b = 2*1 + 1 ≠ 2*(-1) + (-1)

B) ab + 2a =  1*1 + 2*1 ≠ (-1)*(-1) + 2*(-1)  

C) 5a + 6b = 5*1 + 6*1 ≠ 5*(-1) + 6*(-1)    

D) ab + 2b = 1*1 + 2*1 ≠ (-1)*(-1) + 2*(-1)  

E) ab + ab = 1*1 + 1*1 = (-1)*(-1) + (-1)*(-1) -> this is satisfied for every integers a and b

answer: i cant see the graphs but i can you find the answer

step-by-step explanation:

the first point we'll be 0,0 and then you go up the y axis 4 places and over to the right 1 so your second point will be 1,4

the expected value of the random variable : 0, 1 and 2

step-by-step explanation: