In engineering and product design, it is important to consider the weights of people so that airplanes or elevators aren't overloaded. based on data from the national health survey, we can assume the weight of adult males in the us has a mean weight of 177 pounds and standard deviation of 32 pounds. we randomly select 50 adult males. what is the probability that the average weight of these 50 adult males is over 190 pounds?

0.002

Step-by-step explanation:

We need to estimate the standard error of the mean, so we can use it as a standard deviation of the sample of 50 males.

Standard error of the mean = standard deviation/√n

Standard error of the mean = 32/√50 = 4.52

Now we can use this Standard error of the mean to estimate z as follows:

Z = (x – mean)/standard deviation

Z = (190-177)/4.52

Z = 2.87

Using  a Z table we can find probability that mean is under 190

P (z<190)= 0.998

For the probability that the mean exceed 190 lbs we substract from 1

P(z>190) = 1 - 0.998 = 0.002

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.