The table below shows all of the possible outcomes for rolling two six sided number cubes what is the probability of rolling an even number first and an odd number second

The probability of rolling an even number first and an odd number second is

Solution:

As two cubes are 6 sided,  the total number of possibilities are

Now in those possibilities the first number will be even and the second number will be odd.  If we check the table, such pairs are,  

(2,1), (2,3), (2,5), (4,1), (4,3), (4,5), (6,1), (6,3), (6,5)

So, we can see we have total 9 set with the combination of first number even and second number odd.  So, the probability of rolling with this combination will be

i dont know sorry

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.