![\bf y-3=-\cfrac{3}{2}(x+3)\implies y-\stackrel{\stackrel{y_1}{\downarrow }}{3}=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}[x-(\stackrel{\stackrel{x_1}{\downarrow }}{-3})]~\hfill \impliedby \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{slope}{-\cfrac{3}{2}}\qquad \qquad \qquad \stackrel{point}{(-3,3)}~\hfill](/tpl/images/0295/7753/ae0ef.png)
Y- 3 = - 3/2 (x + 3)
find the lines slope and a point on the line...
Mathematics, 07.10.2019 02:30 maddie306
Y- 3 = - 3/2 (x + 3)
find the lines slope and a point on the line
Answers: 1
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