Astreet light is mounted on a pole. the tip of the shadow of a man who is standing on a street a short distance from the pole has an angle of elevation to the top of his head of 30°. a woman standing in the opposite direction of the pole as the man was standing on the same street has a angle of elevation from the tip of her shadow to her head of 41°. if the two people are 40 feet apart, how far is the street light from the head of the woman?

  21.15 ft

Step-by-step explanation:

The angle at the lamp between the two shadow tips is ...

  180° -30° -41° = 109°

This angle is opposite the 40-ft side of the triangle. The distance (d) in question is opposite the 30° angle, so can be found from the Law of Sines as ...

  d/sin(30°) = 40'/sin(109°)

  d = (40')·sin(30°)/sin(109°) ≈ 21.152'

The distance from the light to the woman's head is about 21.15 feet.

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We have to assume the heads are at the same height.

4 + 5 7/9= 9 7/9

step-by-step explanation:

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