The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . the object is dropped again from a different starting height so that it hits the ground 0.5 seconds sooner. write a function f that models the path of the object the second time it is dropped.

Check the picture below.

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

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step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632