Arectangular computer table measures 30 inches by 50 inches. we need to cover it with square tiles. what is the side length of the largest square tile we can use to completely cover the table without overlap or gaps?
a. if we use sq
b. if this were a giant chunk of cheese in a factory, would it change the thinking or the calculations we just did?
c. how many 10 inch × 10 inch squares of cheese could be cut from the giant 30 inch × 50 inch slab?

a) 10*10 inch, b)yes, c) 15

Step-by-step explanation:

a)

we need to calculate the Greatest Common Factor between 30 and 50

then, the square tiles will be 10 inch *10 inch

b) it will change because they don't need to have the largest slab possible so they will use any other comon factor with a size they consider correct for the cheese.

c)

15 squares of 10inch*10inch of cheese could be cut.

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.