The sand pit for the long jump has a width of 2.75 meters and a length of 9.54 meters. just in case it rains, the principal wants to cover the sand pit with a piece of plastic the night before the event. how many square meters of plastic will the principal need to cover the sand pit?

The principal will need 26.24 m² of plastic to cover the sand pit.

Step-by-step explanation:

In order to calculate the amount of plastic, we need to find out the area of the sandpit. The shape of the sandpit is a rectangle, so we can use the formula:

A=W×H

where,

W is the width of the sandpit

L is the length of the sandpit

Therefore,

A=2.75 m × 9.54 m = 26.24 m²

The amount of plastic needed is 26.24 m²

the height of the surface increases from the center out to the sides of the road

it is c!

the answer to this is a. a^2 + b^2 = c^2