What is the slope of a line passing through (3, 8) and (5, 5)?

Step-by-step explanation:

bYour input is P=(3,8) and Q=(5,5).

The slope of the line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=3, y1=8, x2=5, y2=5.

Plug the given values into the formula for the slope: m=(5)−(8)(5)−(3)=−32=−32.

Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).

b=8−(−32)⋅(3)=252.

Finally, the equation of the line can be written in the form y=mx+b.

y=−32x+252.

The slope of the line is m=−32=−1.5.

The y-intercept is (0,252)=(0,12.5).

The equation of the line in the slope-intercept form is y=−32x+252=−1.5x+12.5