Mathematics, 03.10.2019 00:30 andrewgainey1986
Suppose that (a, m) = 1. if a = +1, the solution of ax = 1 (mod m') is obviously x = a(mod m'). if a = +2, then m is odd and x = (1 - m')}a (mod m') is the solution of ax = 1(mod m'). for all other a use problem 11 to show that the solution of ax = 1(mod m ) is x = k (mod m') where k is the nearest integer to -(1/a)(1 β ax,)'.
Answers: 3
Mathematics, 21.06.2019 16:00
Which segments are congruent? o jn and ln o jn and nm o in and nk onk and nm
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Mathematics, 21.06.2019 16:50
If the table of the function contains exactly two potential turning points, one with an input value of β1, which statement best describes all possible values of m? m β₯ β12 β12 < m < 4 m β€ 4 m β₯ 4 or m β€ β12
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Mathematics, 21.06.2019 23:00
Erik buys 2.5 pounds of cashews. if each pound of cashews costs $7.70, how much will he pay for the cashews?
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Mathematics, 22.06.2019 00:00
Define the type of sequence below. 7, 14, 28, 56, 112, a. neither arithmetic nor geometric b. arithmetic c. both arithmetic and geometric d. geometric
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Suppose that (a, m) = 1. if a = +1, the solution of ax = 1 (mod m') is obviously x = a(mod m'). if a...
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