In a small private school, five students are randomly selected from eighteen available students. what is the probability that they are the five youngest students?

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18−5)!)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18.  Only 1 of those groups contains the five youngest students.  So the probability is:

P = 1 / 8568 ≈ 0.0117%

true

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl