Aline passes (2,-1) and (4,-5). which is the equation of the line?

y= -2x + 3

Step-by-step explanation:

y-y1 = m(x-x1)

-5-(-1) = m(4-2)

-5+1 = m (2)

-4 = 2m

-4/2 = m

m= -2

Hence, your slope is -2.

But we still need the y-intercept to find the equation.

Hence, use one of the points and the slope to determine the y-int.

y=mx+b

-1 = -2(2) + b

-1 = -4 +b

-1+4 = b

b = 3

Hence the equation of the line is:

y= -2x+3

Hope this helps!

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.