Another rock in death valley at the racetrack traveled 55.3 meters during the observation period of nine years. a . what was the rock's average speed in feet per year? round your answer to the nearest whole number. feet per year b . if a strong wind gives a stone an initial velocity of v 0 = 11 m / s , and the friction coefficient of stone on ice is μ = 0.14 , and g = 9.81 m / s 2 . use the equation v 2 0 = 2 μ g s to find the stopping distance s for the stone. round your answer to the nearest tenth.

a) 20 feet per year

b) 44.1 m

Step-by-step explanation:

Given:

Distance traveled during the observation period = 55.3 meters

Observation period = 9 years

initial velocity of v₀ = 11 m/s

friction coefficient of stone on ice is μ = 0.14

g = 9.81 m/s²

also,

v₀² = 2μgS

Now,

1 m = 3.28084 ft

thus,

Total distance in feet = 55.3 × 3.28084 = 181.430452 ft

Average speed =

or

Average speed =

or

Average speed = 20.159 feet/year ≈ 20 feet per year

b) v₀² = 2μgS

substituting the values in the above equation, we get

11² = 2 × 0.14 × 9.81 × s

or

121 = 2.7468 × s

or

s = 44.051 ≈ 44.1 m

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."