Acommittee of 2 people is to be chosen from 5 women and 5 men. what is the probability at least one man was chosen given at least one woman was chosen?

5/9

Step-by-step explanation:

At the beginning, there are 5 + 5 = 10 people to choose from. After one woman is chosen, that number goes down to 10 - 1  = 9 people. 5 men are still left to choose from, so there is a 5/9 chance at least one man will be selected as the other committee member.

5/7

Step-by-step explanation:

Number of women = 5

Number of men = 5

2 people is to be chosen to form a committee.

Let as assume

A : At least one man was chosen

B : At least one woman was chosen

A ∩ B : Exactly one man and one woman was chosen

P(B) = Exactly one woman was chosen + Two women was chosen

We need to find the probability at least one man was chosen given at least one woman was chosen.

Therefore, the required probability is 5/7.

hkhkhkhkhkhkhk

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b