Find three consecutive integers such that the largest is 3 less than twice the smallest

The three consecutive integers are 5,6,7

Step-by-step explanation:

Let the three consecutive integers be represented as x,x+1,x+2

As per the requirement, largest integer is 3 less than twice the smallest.

=> x+ 2 = 2x -3

=> 2x -x = 2+3

=> x= 5

So the three integers are 5,6,7

Verification:

Largest integer = 7

Smallest integer = 5

2 * smallest integer - 3 = 2* 5 - 3 = 7

Largest integer is also 7.

So the required condition in the question is satisfied by these three integers.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

b.my answer is b.

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