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r and s are the midpoints of xwand yw respectively.

what is the perimeter of △wxy?

86

Step-by-step explanation:

Perimeter of WXY = WSY+WRX+XY

--> WSY = SY x 2

--> WSY = 16 x 2 = 32

Since it is an isosceles triangle, WRX = WSY

--> WRX = 32

--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.

--> Solve it using the cos theta rule

--> Angle = Angle X = 70°

    Hypotenuse = WRX = 32

    Adjacent = WA = ?

--> Cos (Angle) = Adjacent/Hypotenuse

    Cos (70) = WA/32

    WA = 10.9 rounded off to 11

--> WA=AY= 11

--> XY = WA + AY = 11+11 = 22

--> Perimeter = WSY+WRX+XY

    Perimeter = 32+32+22

    Perimeter = 86

Therefore, the perimeter of WXY is 86.

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step-by-step explanation:

i am unable to solve this problem

step-by-step explanation: