Joe and pete each have two cents in their pockets. they have decided to match pennies; that is, they will each take one of their own pennies and flip them. if the pennies match (two heads or two tails), joe gets pete’s penny; if the pennies do not match, pete gets joe’s penny. they will keep repeating the game until one of them has four cents, and the other one is broke. although they do not realize it, all four pennies are biased. the probability of tossing a head is 0.6, and the probability of a tail is 0.4. let x be a markov chain where xn denotes the amount that joe has after the n-th play of the gam a) give the markov matrix for x

b) what is the probability that joe will have four pennies after the second toss?

c) what is the probabilty that pete will be broke after 3 tosses?

d) what is the probability that the game will be over after the third toss?

e) what is the expected amount of money pete will have after two tosses?

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;