Aproduce supplier ships boxes of produce to individual customers. the distribution of weights of shipped boxes is approximately normal with mean 36 pounds and standard deviation 4 pounds. which expression represents the weight, in pounds, at the 75th percentile of the distribution?

(a) -1.96(4)+ 36
(b) -0.25(4) + 36
(c) 0.25(4)+ 36
(d) 0.67(4)+ 36
(e) 0.75(4)+ 36

Option D.

Step-by-step explanation:

Given information: The distribution of weights of shipped boxes is approximately normal.

Population mean = 36

Standard deviation = 4

We need to find the 75th percentile of the distribution

75% = 0.75

From z-table it is clear that the value of z at 0.75 is 0.674.

75th percentile = Mean + z value at 75%(Standard deviation)

75th percentile = 36 + 0.674(4)

In can be rewritten as

75th percentile = 0.67(4) + 36

Therefore, the correct option is D.

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