Atortoise and a hare are competing in a 1200-meter race. the arrogant hare decides to let the tortoise have a 540-meter head start. when the start gun is fired the hare begins running at a constant speed of 9 meters per second and the tortoise begins crawling at a constant speed of 6 meters per second. let t represent the number of seconds that have elapsed since the start gun was fired. write an expression in terms of t that represents the hare's distance from the starting line (in meters). write an expression in terms of t that represents the tortoise's distance from the starting line (in meters). write an expression in terms of t that represents the number of meters the tortoise is ahead of the hare. who finishes the race first?

hare : A = 9t

tortoise: B = 540 + 6t

ahead: C = 540 - 3t

Step-by-step explanation:

Hi!

Lets call A to the distance of the hare to the starting line, and B the distance of the tortoise from the starting line.

At t = 0, A = 0 and B = 540. Then:

The number of meters (we call it C) the tortoise is ahead of the hare is:

To know who finishes first, we can find where both meet (the hare overtakes the tortoise). This happens when C = 0. The time of this event is t = 540/3 = 180.

How far are the runners at t = 180 ? At this time A = 9*180 =  1620 > 1200. Then the winner is the tortoise.

black/brown

step-by-step explanation:

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i dont know sorry

step-by-step explanation: