In 2002, tim was twice as old as sue. in 1997 the sum of their ages was 32. in what year will sue's age be three-fourths tim's age

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = X years

In 1997, Let Sue's age = Y years

After 5 years in 2002, Tim's age = (X+ 5) years

After 5 years in 2002, Sue's age = (Y + 5) years

Now, According to question,

X + Y = 32    (sum of their ages) .......(1)

Y = 32 - X

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of Y in (2)

X + 5 = 2 (32 - X + 5)

X + 5 = 2 (37 - X )

X + 5 = 74 - 2X

3X = 69

X = 69/3 = 23

Now ∵ Y = 32 - X  and X = 23

∴ Y = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after t years = (9 + t) years.

Tim's age after t years = (23 + t) years

According to question,

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

the answer is a.

step-by-step explanation:

in three games of golf, alex shot two under par four times.

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15