Acandy store makes a 9 lbs. mixture of reese’s pieces, m& m’s, and hershey’s kisses. reese’s cost $2.80 per pound, m& m’s cost $2.50, and hershey’s kisses cost $1.20 per pound. the mixture calls for four pounds more reese’s pieces than m& m’s. the total cost of the mixture is $23.00. how much of each ingredient did the store use? write the system of equations to solve this problem

Step-by-step explanation:

Let r, m, h represent the numbers of pounds of Reese's Pieces, M&Ms, and Hershey's Kisses, respectively. The equations shown above represent the relationships described in the problem statement.

The first equation says the total amount of candy is 9 pounds.

The second equation says there are four more pounds of Reese's than of M&Ms.

The third equation says the total cost of the mix is $23.

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The solution can be found by various means to be ...

the mix consists of

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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true

explanation: