Asolider is parachute training. he jumps out of a plane high enough that the pilot determines the solider will land somewhere in an 240 foot radius land zone. the pilow forgot to mention to the solider that the parachute has very little maneuverablity (no steering). and there are 30 trees in the landing zone. each tree from the air practically outlines a circle with a radius of 8 feet. what is the geometric probability that the solider will land in a tree?

  1/30

Step-by-step explanation:

The area of the landing zone is ...

  A = πr² = π·240²

  landing zone area = π(30²)(8²)

The area of a tree is ...

  A = πr² = π·8²

so the area of 30 trees is ...

  total tree area = 30(π·8²)

and the probability of landing in a tree is the ratio of areas:

  p(landing in tree) = (total tree area)/(landing zone area)

  = (π·30·8²)/(π·30²·8²) = 1/30

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4