On a coordinate plane, a line goes through (negative 5, negative 4) and (0, negative 3). a point is at (negative 2, 2). what is the equation of the line that is parallel to the given line and passes through the point (–2, 2)? y = one-fifthx + 4 y = one-fifthx + twelve-fifths y = –5x + 4 y = –5x + twelve-fifths

Second option: 

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

Where "m" is the slope and "b" is the y-intercept.

We know that a line goes through the points and

Since the line intersects the y-axis when , then the y-intercept of this line is:

Substitute the y-intercept and coordinates of the point   into the equation and solve for "m":

By definition, the slopes of parallel lines are equal, then the slope of the other line is:

Knowing that it passes through the point , we can substitute values into the equation   and solve for "b":

Therefoe, the equation of this line is:

i don't see any steps below, sweetheart