Acircle is centered at o(0,0)parenthesis and has a radius of sqrt{29}
29
square root of, 29, end square root.
where does the point t(5,-2) lie? inside the circle, outside the circle or on the circle?

the point T lie on the circle

Step-by-step explanation:

Then the point T lie on the circle.

Check the attached picrude.

ok then what happened.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15