What is distance between line 12x+35y+5=0 and point (2,0).

29 / 37

Step-by-step explanation:

The distance between a point (p, q) and a line ax + by + c = 0 is:

d = | ap + bq + c | / √(a² + b²)

Here, a = 12, b = 35, c = 5, p = 2, and q = 0.

d = | (12)(2) + (35)(0) + 5 | / √(12² + 35²)

d = 29 / 37

The distance between line 12x+35y+5=0 and point (2,0) is units.

Step-by-step explanation:

The distance between a line and a point is

The distance between line 12x+35y+5=0 and point (2,0) is

On further simplification we get

Therefore, the distance between line 12x+35y+5=0 and point (2,0) is units.

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

step-by-step explanation:

bob the banana