Find the 100th and the nth term for each of the following sequences. a. 1,3,5,7 b. 50, 90, 130 c. 1.3.9. d. 9.93.95.97 e. 142+7.229.142+8.229.142 +9.229

a) the 100th term is 199 and the nth term is 2n-1.

b) the 100th term is 4010 and the nth term is 40n + 10

c) the 100th term is 60.7 and the nth term is .6n +.7

d) The 100th term is 11.91 and the nth term is 9.91 + 0.02n

e) The 100th term is 142 +106.229 and the nth term is 142 + (6.229+n)

Step-by-step explanation:

The formula to find the nth term of a sequence is:

Where is the nth term, is the first one and d is the difference between each term.

So now we're going to apply this to our sequences

a) 1, 3, 5, 7...

First term = 1

Difference = 2

nth term = = 1 + 2n - 2 = 2n - 1

100th term= 2(100) - 1 = 200 - 1 = 199

b) 50, 90, 130...

First term = 50

Difference = 40

nth term = 50 + 40(n - 1) = 50 +40n - 40 = 40n + 10

100th term = 40(100) + 10 = 4000 + 10 = 4010

c) 1.3, 1.9...

First term = 1.3

Difference = .6

nth term =

100th term = .6(100) +.7 = 60 + .7 = 60.7

d) 9.93, 9.95, 9.97...

First term = 9.93

Difference = .02

nth term =

100th term = 9.91+.02(100) = 9.91 + 2 = 11.91

e) 142+7.229, 142+8.229...

First term = 142 +7.229

Difference = .02

nth term =

100th term= 142 + (6.229 + 100) = 142 + 106.229

57 732

step-by-step explanation:

i dont really.know

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: