The sum of three consecutive numbers is one hundred twenty . what is the smallest of the three numbers ?

The answer to your question is 39

Step-by-step explanation:

Three consecutive numbers is 120

The smallest is = ?

The smallest will be n

The next one will be  = n + 1

The highest will be = n + 2

Now, we add them

                         n + n + 1 + n + 2 = 120            Simplify like terms

                         3n + 3 = 120

                         3n = 120 - 3

                         3n = 117

                         n = 117 / 3

                         n = 39

n + 1 = 40

n + 2 = 41

                        39 + 40 + 41 = 120