Solve the following linear programming problem.
maximize:
z = 4x + 9y
subject to:
6x + 7y less than or equals42
12x + y less than or equals42
  x greater than or equals0, y greater than or equals0
the maximum value is?

Find the intersection point between the 2 restraint equations:

30 - 2x = 12 - \frac{1}{2} x \\ \frac{3}{2} x = 18 \\ x = 12

Substitute back in to find y-value:

y = 30 - 2(12) = 6

P is maximized at point (12,6)

P = 9(12)+9(6) = 162

what?

step-by-step explanation:

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.